Solution Bank Trigonometry Target A
Answers to the Practice Problems are below in random order.
\(\begin{align}&x = 8\sqrt{13}, y = 16\ & \ \ \ &
\sec\theta = \frac{5}{3}, \normalsize \csc\theta = \frac{5}{4}, \normalsize \cot\theta = \frac{3}{4}\\\\
&680\ & \ \ \ &
x = 5, y = 5\\\\
&\sec \theta = \frac{13}{6}, \normalsize \csc \theta = \frac{13\sqrt{133}}{133}, \normalsize \cot \theta = \frac{\sqrt{133}}{6}\ & \ \ \ &
YZ = 1.21\\\\
&45.72\ & \ \ \ &
1070\\\\
&\cos\theta = \frac{3}{5}, \normalsize \tan\theta =\frac{4}{3}\ & \ \ \ &
\sin\phi = \frac{6}{13}, \normalsize \cos\phi = \frac{\sqrt{133}}{13}, \normalsize \tan\phi =\frac{\sqrt{133}}{6}\\\\
&\frac{1}{2}\normalsize \log_b x\ & \ \ \ &
46.7^{\circ}\\\\
&x = 18.85, y = 20.47\ & \ \ \ &
f^{-1}(x) = \sqrt{x+3} + 1\\\\
&57.93^{\circ}\ & \ \ \ &
\sec\phi =\frac{13\sqrt{133}}{133}, \normalsize \csc\phi =\frac{13}{6}, \normalsize \cot\phi = \frac{6\sqrt{133}}{133}\\\\
&\sin\theta = \frac{\sqrt{133}}{13}, \normalsize \cos\theta = \frac{6}{13}, \normalsize \tan\theta = \frac{6\sqrt{133}}{133}\ & \ \ \ &
c\\\\
&\frac{2}{3}\ & \ \ \ &
22.0^{\circ}\\\\
&81\ \text{square units}\ & \ \ \ &
30\ \text{units}\\\\
&68^{\circ}\ & \ \ \ &
XY = 3.24\\\\
&x = 8.75, y = 4.85\ & \ \ \ &
30^{\circ}, 60^{\circ}\end{align}\)
Answers to the Practice Problems are below in random order.
\(\begin{align}&x = 8\sqrt{13}, y = 16\ & \ \ \ &
\sec\theta = \frac{5}{3}, \normalsize \csc\theta = \frac{5}{4}, \normalsize \cot\theta = \frac{3}{4}\\\\
&680\ & \ \ \ &
x = 5, y = 5\\\\
&\sec \theta = \frac{13}{6}, \normalsize \csc \theta = \frac{13\sqrt{133}}{133}, \normalsize \cot \theta = \frac{\sqrt{133}}{6}\ & \ \ \ &
YZ = 1.21\\\\
&45.72\ & \ \ \ &
1070\\\\
&\cos\theta = \frac{3}{5}, \normalsize \tan\theta =\frac{4}{3}\ & \ \ \ &
\sin\phi = \frac{6}{13}, \normalsize \cos\phi = \frac{\sqrt{133}}{13}, \normalsize \tan\phi =\frac{\sqrt{133}}{6}\\\\
&\frac{1}{2}\normalsize \log_b x\ & \ \ \ &
46.7^{\circ}\\\\
&x = 18.85, y = 20.47\ & \ \ \ &
f^{-1}(x) = \sqrt{x+3} + 1\\\\
&57.93^{\circ}\ & \ \ \ &
\sec\phi =\frac{13\sqrt{133}}{133}, \normalsize \csc\phi =\frac{13}{6}, \normalsize \cot\phi = \frac{6\sqrt{133}}{133}\\\\
&\sin\theta = \frac{\sqrt{133}}{13}, \normalsize \cos\theta = \frac{6}{13}, \normalsize \tan\theta = \frac{6\sqrt{133}}{133}\ & \ \ \ &
c\\\\
&\frac{2}{3}\ & \ \ \ &
22.0^{\circ}\\\\
&81\ \text{square units}\ & \ \ \ &
30\ \text{units}\\\\
&68^{\circ}\ & \ \ \ &
XY = 3.24\\\\
&x = 8.75, y = 4.85\ & \ \ \ &
30^{\circ}, 60^{\circ}\end{align}\)