Solution Bank Quadratic Functions Target B
Answers to the Practice Problems are below in random order.
Solutions for Problems 1-15.
\(\begin{align}&4x(x-5)\ & \ \ \ \ &-6x(4x+1)\ & \ \ \ \ &4(4x-5)(x+3)\\\\
&7x(7x^2-4x+1)\ & \ \ \ \ &(x-3)(x+6)\ & \ \ \ \ &(2x+5)(x-2)\\\\
&(x-9)(x+4)\ & \ \ \ \ &(x+7)(x+2)\ & \ \ \ \ &3(x+5)(x-6)\\\\
&(7x-1)(x-3)\ & \ \ \ \ &(x-10)(x-1)\ & \ \ \ \ &(2x+1)(x+5)\\\\
&5(3x+2)(x-2)\ & \ \ \ \ &(2x+1)(x+6)\ & \ \ \ \ &(6x+1)(x-3)\end{align}\)
Solutions for Problems 16-30.
\(\begin{align}&(3x-5)^2\ & \ \ \ \ &3(2x+3)^2\ & \ \ \ \ &(4x-7)(4x+7)\\\\
&(4x+1)^2\ & \ \ \ \ &2(x-6)^2\ & \ \ \ \ &(x-8)(x+8)\\\\
&(3x+4)(2x-5)\ & \ \ \ \ &(x-4)(x+4)\ & \ \ \ \ &2(9x-1)(9x+1)\\\\
&10x(2x+1)(x-1)\ & \ \ \ \ &5(x+5)(x-5)\ & \ \ \ \ &-3x(3x-1)(x+2)\\\\
&-2x(3x-2)(x+6)\end{align}\)
\(\begin{align}&V(5,-8); x=5; (7,0), (3,0);\ \text{Domain:}\ (-\infty,\infty)\ \text{Range:} [-8,\infty)\\\\
&V(-1,-8);\ \text{Domain:}\ (-\infty,\infty)\ \text{Range:}\ [-8,\infty); f(x)=2(x+3)(x-1)\\ &\text{Factoring gives you the two x-intercepts to plot as points on the graph}\end{align}\)
Answers to the Practice Problems are below in random order.
Solutions for Problems 1-15.
\(\begin{align}&4x(x-5)\ & \ \ \ \ &-6x(4x+1)\ & \ \ \ \ &4(4x-5)(x+3)\\\\
&7x(7x^2-4x+1)\ & \ \ \ \ &(x-3)(x+6)\ & \ \ \ \ &(2x+5)(x-2)\\\\
&(x-9)(x+4)\ & \ \ \ \ &(x+7)(x+2)\ & \ \ \ \ &3(x+5)(x-6)\\\\
&(7x-1)(x-3)\ & \ \ \ \ &(x-10)(x-1)\ & \ \ \ \ &(2x+1)(x+5)\\\\
&5(3x+2)(x-2)\ & \ \ \ \ &(2x+1)(x+6)\ & \ \ \ \ &(6x+1)(x-3)\end{align}\)
Solutions for Problems 16-30.
\(\begin{align}&(3x-5)^2\ & \ \ \ \ &3(2x+3)^2\ & \ \ \ \ &(4x-7)(4x+7)\\\\
&(4x+1)^2\ & \ \ \ \ &2(x-6)^2\ & \ \ \ \ &(x-8)(x+8)\\\\
&(3x+4)(2x-5)\ & \ \ \ \ &(x-4)(x+4)\ & \ \ \ \ &2(9x-1)(9x+1)\\\\
&10x(2x+1)(x-1)\ & \ \ \ \ &5(x+5)(x-5)\ & \ \ \ \ &-3x(3x-1)(x+2)\\\\
&-2x(3x-2)(x+6)\end{align}\)
\(\begin{align}&V(5,-8); x=5; (7,0), (3,0);\ \text{Domain:}\ (-\infty,\infty)\ \text{Range:} [-8,\infty)\\\\
&V(-1,-8);\ \text{Domain:}\ (-\infty,\infty)\ \text{Range:}\ [-8,\infty); f(x)=2(x+3)(x-1)\\ &\text{Factoring gives you the two x-intercepts to plot as points on the graph}\end{align}\)