Solution Bank Sequences and Series Target A
Answers to the Extended Problems are below in random order.
\(\begin{align}&{a}_{n}=2{n}^{2}+5n-7\ & \ \ &
\sum_\limits{n=1}^{7}(-1)^{n-1}3(\frac{1}{4})^{n-1}\\\\
&f(x)=\frac{n(n+1)}{2}\ & \ \ &
\frac{x^2+1}{2x}+\frac{4x^2+2}{2x}+\frac{9x^2+3}{2x}+\frac{16x^2+4}{2x}+\frac{25x^2+5}{2x}\\\\
&f(x)=\frac{2n+3}{n^2+n}\ & \ \ &
(-1)^{n-1}(2n - 1)\\\\
&\left(\frac{n}{1}\right)^{-1^{n}}\end{align}\)
Answers to the Extended Problems are below in random order.
\(\begin{align}&{a}_{n}=2{n}^{2}+5n-7\ & \ \ &
\sum_\limits{n=1}^{7}(-1)^{n-1}3(\frac{1}{4})^{n-1}\\\\
&f(x)=\frac{n(n+1)}{2}\ & \ \ &
\frac{x^2+1}{2x}+\frac{4x^2+2}{2x}+\frac{9x^2+3}{2x}+\frac{16x^2+4}{2x}+\frac{25x^2+5}{2x}\\\\
&f(x)=\frac{2n+3}{n^2+n}\ & \ \ &
(-1)^{n-1}(2n - 1)\\\\
&\left(\frac{n}{1}\right)^{-1^{n}}\end{align}\)