Solution Bank Exponential & Logarithmic Functions Target D
Answers to the Extended Problems are below in random order.
\(\begin{align}&f^{-1}(x)=\left(\frac{x-4}{-5}\right)^{3}\ & \ \ &-6\ & \ \ & -4\\\\
&4\ & \ \ &f^{-1}\left(x\right)=10^{4x}-6\ & \ \ &f^{-1}(x)=\frac{7x}{x-4}\\\\
&f^{-1}\left(x\right)=3^{x-8}\ & \ \ & 4\ & \ \ &f^{-1}(x) = \sqrt[3]{2-x}\\\\
&f^{-1}{x}=\ln\left(\sqrt{\frac{x}{3}}\right)+\frac{1}{2}\ & \ \ &
\text{Not Inverses}\end{align}\)
Answers to the Extended Problems are below in random order.
\(\begin{align}&f^{-1}(x)=\left(\frac{x-4}{-5}\right)^{3}\ & \ \ &-6\ & \ \ & -4\\\\
&4\ & \ \ &f^{-1}\left(x\right)=10^{4x}-6\ & \ \ &f^{-1}(x)=\frac{7x}{x-4}\\\\
&f^{-1}\left(x\right)=3^{x-8}\ & \ \ & 4\ & \ \ &f^{-1}(x) = \sqrt[3]{2-x}\\\\
&f^{-1}{x}=\ln\left(\sqrt{\frac{x}{3}}\right)+\frac{1}{2}\ & \ \ &
\text{Not Inverses}\end{align}\)